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Thabiso KaliEnergy engineer · CEM

For engineers and facility managers

Motor and VSD savings for pumps and fans

Pumps and fans that run at full speed and throttle their flow waste energy against a valve or damper. A variable-speed drive slows the machine instead, and the affinity laws say power falls much faster than flow.

Inputs

Pre-filled with an illustrative case. Results update as you type. Jump to results

Motor and operation
kW
%

Share of rated power at design flow.

h/yr
R/kWh
Duty profile

Flow as % of design flow, and the share of running hours at that flow. Time shares must add up to 100%.

System

Sets how today's power falls with flow (see the method).

%

Throttle/damper ≈ 60% (assumed); bypass 100%.

%

0 for fans and closed loops; the lift share of total head for pumps.

Drive
Drive
%
%
R/kW

Results

A VSD saves about 107,294 kWh a year (28%), worth R150k; payback 1.2 years.

Energy saved
107,294kWh
28% of today's use
Annual saving
R150k
At R1.40/kWh
VSD cost
R188k
75.0 kW drive
Simple payback
1.2years
Before maintenance and incentives

NoteToday's power at reduced flow is an assumption (60% at zero flow, rising in a straight line). Measured kW at two flows would firm it up.

Power against flow

Electrical input as a share of today's full-flow power. The gap between the lines at your duty points is the saving. Hover for values.

  • Today
  • With VSD
0%20%40%60%80%100%20%30%40%50%60%70%80%90%100%D4D3D2D1With VSDTodayFlow (% of design)

Duty points

kW is electrical input. Scroll sideways on a phone.

PointFlowHoursToday kWVSD kWToday kWhVSD kWh
D1100%1,50067.169.2100,658103,771
D290%2,10064.450.4135,284105,909
D375%1,80060.429.2108,71152,534
D460%60056.414.933,8218,966
Total–6,000––378,474271,180

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Save this result as one measure in a project kept in this browser, then combine it with results from other tools for payback, NPV, IRR and a cost curve.

Saving, year 1
R150,212/yrAssumed
Energy saved
107,294 kWh/yrAssumed
Capex
R187,500Assumed

Every input above is still the illustrative example, so the result is tagged assumed. Enter your own numbers to make it yours.

Assumed
years

Drives typically last 10 to 15 years. Default 10.

Assumed
R/yr

Fans, filters and capacitors in the drive. Default: 1% of capex a year.

Method

Affinity laws (same machine, speed ratio n)
Q ∝ n, H ∝ n², P ∝ n³
Exact along the machine's own curve; the system curve decides where it operates.
Power with a VSD at flow fraction q
P_vsd(q) ÷ P_full = q × (h_s + (1 − h_s) × q²) ÷ η_vsd
System curve H = h_s + (1 − h_s) q². With no static head (h_s = 0) this is q³.
Power today at flow fraction q
P_today(q) ÷ P_full = b₀ + (1 − b₀) × q
A straight-line approximation: b₀ ≈ 0.6 assumed for a throttle valve or outlet damper, 1.0 for bypass.
Full-flow electrical input
P_full = rated kW × load fraction ÷ η_motor
Energy and saving
kWh = Σ hours × time share_i × P(q_i), saving = kWh_today − kWh_vsd
Payback
payback = rated kW × R/kW ÷ (saving kWh × R/kWh)

Assumptions

  • Machine and motor efficiencies are held constant across the speed range. In practice both fall at low load, which trims the saving a little.
  • The baseline power curve for throttling or dampers is a straight-line assumption; real curves depend on the machine. Measured kW at two flows is better.
  • Flow requirements are met at every duty point; there is no minimum-speed limit in the calculation.
  • The drive's own losses (default 3%) apply at every speed, so at full flow the drive costs a little energy.
  • Installed VSD cost per kW is illustrative and falls with size; harmonic filters, bypass contactors and cabling can add to it.

Sources

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